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13210101211 is a prime number
BaseRepresentation
bin11000100110110001…
…00010010111011011
31021002122010200010211
430103120202113123
5204023241214321
610022454151551
7645234002416
oct142330422733
937078120124
1013210101211
11566983761a
1226880525b7
131326a84948
148d461ab7d
15524b040e1
hex3136225db

13210101211 has 2 divisors, whose sum is σ = 13210101212. Its totient is φ = 13210101210.

The previous prime is 13210101169. The next prime is 13210101217. The reversal of 13210101211 is 11210101231.

It is a happy number.

13210101211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13210101211 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13210101191 and 13210101200.

It is not a weakly prime, because it can be changed into another prime (13210101217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605050605 + 6605050606.

It is an arithmetic number, because the mean of its divisors is an integer number (6605050606).

Almost surely, 213210101211 is an apocalyptic number.

13210101211 is a deficient number, since it is larger than the sum of its proper divisors (1).

13210101211 is an equidigital number, since it uses as much as digits as its factorization.

13210101211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 13210101211 its reverse (11210101231), we get a palindrome (24420202442).

The spelling of 13210101211 in words is "thirteen billion, two hundred ten million, one hundred one thousand, two hundred eleven".