Base | Representation |
---|---|
bin | 1100000000111100010011… |
… | …0110011111001111000111 |
3 | 1201202220011101221212121210 |
4 | 3000033010312133033013 |
5 | 3212414222211201010 |
6 | 44032423535142503 |
7 | 2532262135143363 |
oct | 300170466371707 |
9 | 51686141855553 |
10 | 13210327053255 |
11 | 4233517257952 |
12 | 15942bb974a33 |
13 | 74a961675497 |
14 | 3395518822a3 |
15 | 17d96e56db20 |
hex | c03c4d9f3c7 |
13210327053255 has 16 divisors (see below), whose sum is σ = 21535325612640. Its totient is φ = 6912573652608.
The previous prime is 13210327053227. The next prime is 13210327053373. The reversal of 13210327053255 is 55235072301231.
It is not a de Polignac number, because 13210327053255 - 219 = 13210326528967 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8308381000 + ... + 8308382589.
It is an arithmetic number, because the mean of its divisors is an integer number (1345957850790).
Almost surely, 213210327053255 is an apocalyptic number.
13210327053255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13210327053255 is a deficient number, since it is larger than the sum of its proper divisors (8324998559385).
13210327053255 is a wasteful number, since it uses less digits than its factorization.
13210327053255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16616763650.
The product of its (nonzero) digits is 189000, while the sum is 39.
Adding to 13210327053255 its reverse (55235072301231), we get a palindrome (68445399354486).
The spelling of 13210327053255 in words is "thirteen trillion, two hundred ten billion, three hundred twenty-seven million, fifty-three thousand, two hundred fifty-five".
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