Search a number
-
+
132110213113120 = 2551175062621087
BaseRepresentation
bin11110000010011101001110…
…010100101110010100100000
3122022202121112220021101100111
4132002131032110232110200
5114303443204024104440
61144550332152301104
736553435144211164
oct3602351624562440
9568677486241314
10132110213113120
1139104699218170
1212997a170a1794
135893c2a512298
14248a250268ca4
1510417532184ea
hex78274e52e520

132110213113120 has 48 divisors (see below), whose sum is σ = 340484049255168. Its totient is φ = 48040077495040.

The previous prime is 132110213113117. The next prime is 132110213113129. The reversal of 132110213113120 is 21311312011231.

It is a super-2 number, since 2×1321102131131202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 132110213113091 and 132110213113100.

It is not an unprimeable number, because it can be changed into a prime (132110213113129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37531308784 + ... + 37531312303.

It is an arithmetic number, because the mean of its divisors is an integer number (7093417692816).

Almost surely, 2132110213113120 is an apocalyptic number.

132110213113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132110213113120 is an abundant number, since it is smaller than the sum of its proper divisors (208373836142048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132110213113120 is a wasteful number, since it uses less digits than its factorization.

132110213113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75062621113 (or 75062621105 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 132110213113120 its reverse (21311312011231), we get a palindrome (153421525124351).

The spelling of 132110213113120 in words is "one hundred thirty-two trillion, one hundred ten billion, two hundred thirteen million, one hundred thirteen thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 11 16 20 22 32 40 44 55 80 88 110 160 176 220 352 440 880 1760 75062621087 150125242174 300250484348 375313105435 600500968696 750626210870 825688831957 1201001937392 1501252421740 1651377663914 2402003874784 3002504843480 3302755327828 4128444159785 6005009686960 6605510655656 8256888319570 12010019373920 13211021311312 16513776639140 26422042622624 33027553278280 66055106556560 132110213113120