Base | Representation |
---|---|
bin | 10011001110010111110… |
… | …101011000001010101111 |
3 | 11200021222220001222102101 |
4 | 103032113311120022233 |
5 | 133121104142441421 |
6 | 2450523411235531 |
7 | 164306101241251 |
oct | 23162765301257 |
9 | 4607886058371 |
10 | 1321102312111 |
11 | 46a3048a565a |
12 | 1940565a8ba7 |
13 | 9776bc8225a |
14 | 47d28011cd1 |
15 | 24571832191 |
hex | 13397d582af |
1321102312111 has 2 divisors, whose sum is σ = 1321102312112. Its totient is φ = 1321102312110.
The previous prime is 1321102312099. The next prime is 1321102312181. The reversal of 1321102312111 is 1112132011231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1321102312111 is a prime.
It is a super-2 number, since 2×13211023121112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321102312181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660551156055 + 660551156056.
It is an arithmetic number, because the mean of its divisors is an integer number (660551156056).
Almost surely, 21321102312111 is an apocalyptic number.
1321102312111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321102312111 is an equidigital number, since it uses as much as digits as its factorization.
1321102312111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1321102312111 its reverse (1112132011231), we get a palindrome (2433234323342).
The spelling of 1321102312111 in words is "one trillion, three hundred twenty-one billion, one hundred two million, three hundred twelve thousand, one hundred eleven".
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