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132110960773 = 1112010087343
BaseRepresentation
bin111101100001001101…
…1010100100010000101
3110122000001002011102011
41323002123110202011
54131030401221043
6140405124214221
712354555431641
oct1730233244205
9418001064364
10132110960773
1151034214210
122172b83a371
13c5c532c64c
1465739a9c21
15368334359d
hex1ec26d4885

132110960773 has 4 divisors (see below), whose sum is σ = 144121048128. Its totient is φ = 120100873420.

The previous prime is 132110960731. The next prime is 132110960801. The reversal of 132110960773 is 377069011231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-132110960773 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132110960573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6005043661 + ... + 6005043682.

It is an arithmetic number, because the mean of its divisors is an integer number (36030262032).

Almost surely, 2132110960773 is an apocalyptic number.

It is an amenable number.

132110960773 is a deficient number, since it is larger than the sum of its proper divisors (12010087355).

132110960773 is a wasteful number, since it uses less digits than its factorization.

132110960773 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12010087354.

The product of its (nonzero) digits is 47628, while the sum is 40.

The spelling of 132110960773 in words is "one hundred thirty-two billion, one hundred ten million, nine hundred sixty thousand, seven hundred seventy-three".

Divisors: 1 11 12010087343 132110960773