132111312 has 80 divisors (see below), whose sum is σ = 355661760. Its totient is φ = 42218496.

The previous prime is 132111293. The next prime is 132111319. The reversal of 132111312 is 213111231.

It is a happy number.

It is a super-2 number, since 2×132111312² = 34906797516722688, which contains 22 as substring.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 132111291 and 132111300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132111319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 129139 + ... + 130157.

It is an arithmetic number, because the mean of its divisors is an integer number (4445772).

Almost surely, 2^132111312 is an apocalyptic number.

132111312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132111312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (177830880).

132111312 is an abundant number, since it is smaller than the sum of its proper divisors (223550448).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132111312 is a wasteful number, since it uses less digits than its factorization.

132111312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1140 (or 1134 counting only the distinct ones).

The product of its digits is 36, while the sum is 15.

The square root of 132111312 is about 11493.9685052640. The cubic root of 132111312 is about 509.3074182210.

Adding to 132111312 its reverse (213111231), we get a palindrome (345222543).

It can be divided in two parts, 1321113 and 12, that added together give a triangular number (1321125 = T₁₆₂₅).

The spelling of 132111312 in words is "one hundred thirty-two million, one hundred eleven thousand, three hundred twelve".