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132112400103333 = 3313376388604283
BaseRepresentation
bin11110000010011111010000…
…101011011011011110100101
3122022202211012022110222221000
4132002133100223123132211
5114304012143411301313
61144551333155143513
736553543301264016
oct3602372053333645
9568684168428830
10132112400103333
11391056107712a1
12129983275a4b99
1358941b863a130
14248a3ba8bb00d
151041830215673
hex7827d0adb7a5

132112400103333 has 16 divisors (see below), whose sum is σ = 210777618399040. Its totient is φ = 81299938524912.

The previous prime is 132112400103301. The next prime is 132112400103361. The reversal of 132112400103333 is 333301004211231.

132112400103333 is a `hidden beast` number, since 1 + 3 + 211 + 2 + 400 + 10 + 3 + 3 + 33 = 666.

It is not a de Polignac number, because 132112400103333 - 25 = 132112400103301 is a prime.

It is a super-2 number, since 2×1321124001033332 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132112400103297 and 132112400103306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132112400108333) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 188194301791 + ... + 188194302492.

It is an arithmetic number, because the mean of its divisors is an integer number (13173601149940).

Almost surely, 2132112400103333 is an apocalyptic number.

132112400103333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

132112400103333 is a deficient number, since it is larger than the sum of its proper divisors (78665218295707).

132112400103333 is a wasteful number, since it uses less digits than its factorization.

132112400103333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 376388604305 (or 376388604299 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 132112400103333 its reverse (333301004211231), we get a palindrome (465413404314564).

The spelling of 132112400103333 in words is "one hundred thirty-two trillion, one hundred twelve billion, four hundred million, one hundred three thousand, three hundred thirty-three".

Divisors: 1 3 9 13 27 39 117 351 376388604283 1129165812849 3387497438547 4893051855679 10162492315641 14679155567037 44037466701111 132112400103333