132114134310040 has 64 divisors (see below), whose sum is σ = 297699153163200. Its totient is φ = 52767064154112.

The previous prime is 132114134310017. The next prime is 132114134310101. The reversal of 132114134310040 is 40013431411231.

It is a junction number, because it is equal to n+sod(n) for n = 132114134309990 and 132114134310008.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 82923184 + ... + 84501376.

It is an arithmetic number, because the mean of its divisors is an integer number (4651549268175).

Almost surely, 2^{132114134310040} is an apocalyptic number.

132114134310040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132114134310040 is an abundant number, since it is smaller than the sum of its proper divisors (165585018853160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132114134310040 is a wasteful number, since it uses less digits than its factorization.

132114134310040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1581316 (or 1581312 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 132114134310040 its reverse (40013431411231), we get a palindrome (172127565721271).

The spelling of 132114134310040 in words is "one hundred thirty-two trillion, one hundred fourteen billion, one hundred thirty-four million, three hundred ten thousand, forty".