Base | Representation |
---|---|
bin | 11000100110111011… |
… | …10100011111111111 |
3 | 1021002201202000222222 |
4 | 30103131310133333 |
5 | 204024120024312 |
6 | 10022543555555 |
7 | 645251531333 |
oct | 142335643777 |
9 | 37081660888 |
10 | 13211486207 |
11 | 566a5a3147 |
12 | 26885bbbbb |
13 | 132714b17a |
14 | 8d489b7c3 |
15 | 524cc9672 |
hex | 3137747ff |
13211486207 has 4 divisors (see below), whose sum is σ = 13217311080. Its totient is φ = 13205661336.
The previous prime is 13211486179. The next prime is 13211486209. The reversal of 13211486207 is 70268411231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13211486207 - 220 = 13210437631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13211486209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2909033 + ... + 2913570.
It is an arithmetic number, because the mean of its divisors is an integer number (3304327770).
Almost surely, 213211486207 is an apocalyptic number.
13211486207 is a deficient number, since it is larger than the sum of its proper divisors (5824873).
13211486207 is an equidigital number, since it uses as much as digits as its factorization.
13211486207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5824872.
The product of its (nonzero) digits is 16128, while the sum is 35.
Adding to 13211486207 its reverse (70268411231), we get a palindrome (83479897438).
The spelling of 13211486207 in words is "thirteen billion, two hundred eleven million, four hundred eighty-six thousand, two hundred seven".
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