Base | Representation |
---|---|
bin | 11110000010100110011110… |
… | …001101111011010111001000 |
3 | 122022210120011221221102120212 |
4 | 132002212132031323113020 |
5 | 114304124023210142100 |
6 | 1144555053405540252 |
7 | 36554236214503340 |
oct | 3602463615732710 |
9 | 568716157842525 |
10 | 132120143443400 |
11 | 391089246772a2 |
12 | 12999928874688 |
13 | 5894b50948368 |
14 | 248a913053d20 |
15 | 1041b34e13635 |
hex | 78299e37b5c8 |
132120143443400 has 96 divisors (see below), whose sum is σ = 351298825227840. Its totient is φ = 45267789116160.
The previous prime is 132120143443399. The next prime is 132120143443469. The reversal of 132120143443400 is 4344341021231.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 29741579 + ... + 33893978.
It is an arithmetic number, because the mean of its divisors is an integer number (3659362762790).
Almost surely, 2132120143443400 is an apocalyptic number.
132120143443400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132120143443400 is an abundant number, since it is smaller than the sum of its proper divisors (219178681784440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132120143443400 is a wasteful number, since it uses less digits than its factorization.
132120143443400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63637063 (or 63637054 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 132120143443400 its reverse (4344341021231), we get a palindrome (136464484464631).
The spelling of 132120143443400 in words is "one hundred thirty-two trillion, one hundred twenty billion, one hundred forty-three million, four hundred forty-three thousand, four hundred".
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