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1321209096479 is a prime number
BaseRepresentation
bin10011001110011110001…
…100101110100100011111
311200022021100000012000222
4103032132030232210133
5133121314012041404
62450542144111555
7164311536011036
oct23163614564437
94608240005028
101321209096479
1146a35a1002a8
121940863055bb
139778812ca7c
1447d3828b71d
152457adc6dbe
hex1339e32e91f

1321209096479 has 2 divisors, whose sum is σ = 1321209096480. Its totient is φ = 1321209096478.

The previous prime is 1321209096437. The next prime is 1321209096481. The reversal of 1321209096479 is 9746909021231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1321209096479 is a prime.

It is a Sophie Germain prime.

Together with 1321209096481, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1321209096479.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1321209096379) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660604548239 + 660604548240.

It is an arithmetic number, because the mean of its divisors is an integer number (660604548240).

Almost surely, 21321209096479 is an apocalyptic number.

1321209096479 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321209096479 is an equidigital number, since it uses as much as digits as its factorization.

1321209096479 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1469664, while the sum is 53.

The spelling of 1321209096479 in words is "one trillion, three hundred twenty-one billion, two hundred nine million, ninety-six thousand, four hundred seventy-nine".