Base | Representation |
---|---|
bin | 11110000010101000101010… |
… | …101011110111110001010111 |
3 | 122022210210021012102011011012 |
4 | 132002220222223313301113 |
5 | 114304143340011301010 |
6 | 1145000123313202435 |
7 | 36554351502000644 |
oct | 3602505253676127 |
9 | 568723235364135 |
10 | 132122500103255 |
11 | 39109923977772 |
12 | 1299a285b6041b |
13 | 5895137c6b04c |
14 | 248aa98030dcb |
15 | 1041c21c78005 |
hex | 782a2aaf7c57 |
132122500103255 has 8 divisors (see below), whose sum is σ = 158547435015600. Its totient is φ = 105697710154816.
The previous prime is 132122500103177. The next prime is 132122500103261. The reversal of 132122500103255 is 552301005221231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132122500103255 - 212 = 132122500099159 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34225670 + ... + 37889859.
It is an arithmetic number, because the mean of its divisors is an integer number (19818429376950).
Almost surely, 2132122500103255 is an apocalyptic number.
132122500103255 is a deficient number, since it is larger than the sum of its proper divisors (26424934912345).
132122500103255 is an equidigital number, since it uses as much as digits as its factorization.
132122500103255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72481953.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 132122500103255 its reverse (552301005221231), we get a palindrome (684423505324486).
The spelling of 132122500103255 in words is "one hundred thirty-two trillion, one hundred twenty-two billion, five hundred million, one hundred three thousand, two hundred fifty-five".
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