Base | Representation |
---|---|
bin | 10011001110100011110… |
… | …110110111111111111111 |
3 | 11200022111221122101000220 |
4 | 103032203312313333333 |
5 | 133122012312444411 |
6 | 2450555414552423 |
7 | 164314100645532 |
oct | 23164366677777 |
9 | 4608457571026 |
10 | 1321304031231 |
11 | 46a3a8752178 |
12 | 1940b2068713 |
13 | 977a19bbb92 |
14 | 47d46b20a19 |
15 | 245843cab06 |
hex | 133a3db7fff |
1321304031231 has 64 divisors (see below), whose sum is σ = 1981954832256. Its totient is φ = 779175936000.
The previous prime is 1321304031193. The next prime is 1321304031319.
1321304031231 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 1321304031231 - 211 = 1321304029183 is a prime.
It is a super-2 number, since 2×13213040312312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1321304081231) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7729521 + ... + 7898613.
It is an arithmetic number, because the mean of its divisors is an integer number (30968044254).
Almost surely, 21321304031231 is an apocalyptic number.
1321304031231 is a deficient number, since it is larger than the sum of its proper divisors (660650801025).
1321304031231 is a wasteful number, since it uses less digits than its factorization.
1321304031231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 169292.
The product of its (nonzero) digits is 1296, while the sum is 24.
The spelling of 1321304031231 in words is "one trillion, three hundred twenty-one billion, three hundred four million, thirty-one thousand, two hundred thirty-one".
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