Base | Representation |
---|---|
bin | 10011001110100100001… |
… | …110011010000011101000 |
3 | 11200022112101020210001022 |
4 | 103032210032122003220 |
5 | 133122020402400130 |
6 | 2451000155112012 |
7 | 164314204250435 |
oct | 23164416320350 |
9 | 4608471223038 |
10 | 1321310200040 |
11 | 46a401185966 |
12 | 1940b4142608 |
13 | 977a306b96c |
14 | 47d47888b8c |
15 | 24584be87e5 |
hex | 133a439a0e8 |
1321310200040 has 32 divisors (see below), whose sum is σ = 2973135511080. Its totient is φ = 528490735872.
The previous prime is 1321310200037. The next prime is 1321310200069. The reversal of 1321310200040 is 400020131231.
It can be written as a sum of positive squares in 4 ways, for example, as 986696542276 + 334613657764 = 993326^2 + 578458^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1321310199991 and 1321310200018.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 395099 + ... + 1672938.
Almost surely, 21321310200040 is an apocalyptic number.
1321310200040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1321310200040 is an abundant number, since it is smaller than the sum of its proper divisors (1651825311040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1321310200040 is a wasteful number, since it uses less digits than its factorization.
1321310200040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2084021 (or 2084017 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1321310200040 its reverse (400020131231), we get a palindrome (1721330331271).
The spelling of 1321310200040 in words is "one trillion, three hundred twenty-one billion, three hundred ten million, two hundred thousand, forty".
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