Base | Representation |
---|---|
bin | 111101100001110111… |
… | …0000001101100000000 |
3 | 110122001112212122211101 |
4 | 1323003232001230000 |
5 | 4131101424012121 |
6 | 140411221024144 |
7 | 12355240631110 |
oct | 1730356015400 |
9 | 418045778741 |
10 | 132132641536 |
11 | 510454822a5 |
12 | 21736b55054 |
13 | c5c9980abc |
14 | 6576811040 |
15 | 36851c7491 |
hex | 1ec3b81b00 |
132132641536 has 72 divisors (see below), whose sum is σ = 311821765920. Its totient is φ = 54675554304.
The previous prime is 132132641519. The next prime is 132132641539. The reversal of 132132641536 is 635146231231.
It is a junction number, because it is equal to n+sod(n) for n = 132132641495 and 132132641504.
It is not an unprimeable number, because it can be changed into a prime (132132641539) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1219321 + ... + 1323256.
It is an arithmetic number, because the mean of its divisors is an integer number (4330857860).
Almost surely, 2132132641536 is an apocalyptic number.
132132641536 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
132132641536 is an abundant number, since it is smaller than the sum of its proper divisors (179689124384).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132132641536 is an equidigital number, since it uses as much as digits as its factorization.
132132641536 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2542629 (or 2542615 counting only the distinct ones).
The product of its digits is 77760, while the sum is 37.
Adding to 132132641536 its reverse (635146231231), we get a palindrome (767278872767).
The spelling of 132132641536 in words is "one hundred thirty-two billion, one hundred thirty-two million, six hundred forty-one thousand, five hundred thirty-six".
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