Base | Representation |
---|---|
bin | 10011001110101011000… |
… | …001011100001001001111 |
3 | 11200022211022211200011010 |
4 | 103032223001130021033 |
5 | 133122234101204411 |
6 | 2451015351300303 |
7 | 164320060503153 |
oct | 23165301341117 |
9 | 4608738750133 |
10 | 1321424241231 |
11 | 46a45a597786 |
12 | 19412637a693 |
13 | 977c088a563 |
14 | 47d58a93063 |
15 | 2458ec237a6 |
hex | 133ab05c24f |
1321424241231 has 4 divisors (see below), whose sum is σ = 1761898988312. Its totient is φ = 880949494152.
The previous prime is 1321424241199. The next prime is 1321424241233.
It is a happy number.
1321424241231 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1321424241231 - 25 = 1321424241199 is a prime.
It is a super-2 number, since 2×13214242412312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1321424241233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220237373536 + ... + 220237373541.
It is an arithmetic number, because the mean of its divisors is an integer number (440474747078).
Almost surely, 21321424241231 is an apocalyptic number.
1321424241231 is a deficient number, since it is larger than the sum of its proper divisors (440474747081).
1321424241231 is an equidigital number, since it uses as much as digits as its factorization.
1321424241231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 440474747080.
The product of its digits is 9216, while the sum is 30.
The spelling of 1321424241231 in words is "one trillion, three hundred twenty-one billion, four hundred twenty-four million, two hundred forty-one thousand, two hundred thirty-one".
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