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132144011120500 = 22532309114459949
BaseRepresentation
bin11110000010111100101100…
…110101111000111101110100
3122022212211210100012001101121
4132002330230311320331310
5114310021413321324000
61145014042021033324
736556042532426641
oct3602745465707564
9568784710161347
10132144011120500
1139117a62321375
12129a2489b55844
1358971856c4812
14248bb38c86dc8
1510425804b7b1a
hex782f2cd78f74

132144011120500 has 48 divisors (see below), whose sum is σ = 288727513074000. Its totient is φ = 52834711996800.

The previous prime is 132144011120497. The next prime is 132144011120503. The reversal of 132144011120500 is 5021110441231.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (132144011120497) and next prime (132144011120503).

It can be written as a sum of positive squares in 8 ways, for example, as 33609522106384 + 98534489014116 = 5797372^2 + 9926454^2 .

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132144011120503) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56075475 + ... + 58384474.

It is an arithmetic number, because the mean of its divisors is an integer number (6015156522375).

Almost surely, 2132144011120500 is an apocalyptic number.

132144011120500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132144011120500 is an abundant number, since it is smaller than the sum of its proper divisors (156583501953500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132144011120500 is a wasteful number, since it uses less digits than its factorization.

132144011120500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114462277 (or 114462265 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 132144011120500 its reverse (5021110441231), we get a palindrome (137165121561731).

The spelling of 132144011120500 in words is "one hundred thirty-two trillion, one hundred forty-four billion, eleven million, one hundred twenty thousand, five hundred".

Divisors: 1 2 4 5 10 20 25 50 100 125 250 500 2309 4618 9236 11545 23090 46180 57725 115450 230900 288625 577250 1154500 114459949 228919898 457839796 572299745 1144599490 2289198980 2861498725 5722997450 11445994900 14307493625 28614987250 57229974500 264288022241 528576044482 1057152088964 1321440111205 2642880222410 5285760444820 6607200556025 13214401112050 26428802224100 33036002780125 66072005560250 132144011120500