Base | Representation |
---|---|
bin | 1100000001100001111110… |
… | …1000011110001111010001 |
3 | 1201210212021012022211222021 |
4 | 3000120133220132033101 |
5 | 3213100430122243101 |
6 | 44041215235411441 |
7 | 2533100554131046 |
oct | 300303750361721 |
9 | 51725235284867 |
10 | 13220440040401 |
11 | 4237836823870 |
12 | 1596262753b81 |
13 | 74b8b38a2849 |
14 | 339c30a171cd |
15 | 17dd622e95a1 |
hex | c061fa1e3d1 |
13220440040401 has 64 divisors (see below), whose sum is σ = 16180529227776. Its totient is φ = 10652977843200.
The previous prime is 13220440040393. The next prime is 13220440040407. The reversal of 13220440040401 is 10404004402231.
It is not a de Polignac number, because 13220440040401 - 23 = 13220440040393 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13220440040407) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 637703206 + ... + 637723936.
It is an arithmetic number, because the mean of its divisors is an integer number (252820769184).
Almost surely, 213220440040401 is an apocalyptic number.
13220440040401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13220440040401 is a deficient number, since it is larger than the sum of its proper divisors (2960089187375).
13220440040401 is a wasteful number, since it uses less digits than its factorization.
13220440040401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23062.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 13220440040401 its reverse (10404004402231), we get a palindrome (23624444442632).
The spelling of 13220440040401 in words is "thirteen trillion, two hundred twenty billion, four hundred forty million, forty thousand, four hundred one".
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