Base | Representation |
---|---|
bin | 1100000001100100100101… |
… | …0110110001100011111000 |
3 | 1201210221001222111201102101 |
4 | 3000121021112301203320 |
5 | 3213103343322402044 |
6 | 44041412523113144 |
7 | 2533124114065663 |
oct | 300311126614370 |
9 | 51727058451371 |
10 | 13221140044024 |
11 | 4238065975960 |
12 | 15964190727b4 |
13 | 74b995913783 |
14 | 339c999926da |
15 | 17dda39bccd4 |
hex | c06495b18f8 |
13221140044024 has 16 divisors (see below), whose sum is σ = 27043240999320. Its totient is φ = 6009609110880.
The previous prime is 13221140044009. The next prime is 13221140044061. The reversal of 13221140044024 is 42044004112231.
It is a super-2 number, since 2×132211400440242 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13221140043983 and 13221140044001.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75120113799 + ... + 75120113974.
Almost surely, 213221140044024 is an apocalyptic number.
It is an amenable number.
13221140044024 is an abundant number, since it is smaller than the sum of its proper divisors (13822100955296).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13221140044024 is a wasteful number, since it uses less digits than its factorization.
13221140044024 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150240227790 (or 150240227786 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 13221140044024 its reverse (42044004112231), we get a palindrome (55265144156255).
The spelling of 13221140044024 in words is "thirteen trillion, two hundred twenty-one billion, one hundred forty million, forty-four thousand, twenty-four".
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