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132213140511500 = 225317311493499649
BaseRepresentation
bin11110000011111101000101…
…010001100101101100001100
3122100010110020002022222020102
4132003331011101211230030
5114312140002432332000
61145105513411510232
736564040605521636
oct3603750521455414
9570113202288212
10132213140511500
1139144307035a74
12129b39612b8378
1358a08516664c9
142491215dd3a56
1510442794553d5
hex783f45465b0c

132213140511500 has 384 divisors, whose sum is σ = 318663072000000. Its totient is φ = 47703416832000.

The previous prime is 132213140511497. The next prime is 132213140511527. The reversal of 132213140511500 is 5115041312231.

It is a happy number.

It is a super-3 number, since 3×1322131405115003 (a number of 43 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 13702258676 + ... + 13702268324.

It is an arithmetic number, because the mean of its divisors is an integer number (829851750000).

Almost surely, 2132213140511500 is an apocalyptic number.

132213140511500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132213140511500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159331536000000).

132213140511500 is an abundant number, since it is smaller than the sum of its proper divisors (186449931488500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132213140511500 is a wasteful number, since it uses less digits than its factorization.

132213140511500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10214 (or 10202 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 132213140511500 its reverse (5115041312231), we get a palindrome (137328181823731).

The spelling of 132213140511500 in words is "one hundred thirty-two trillion, two hundred thirteen billion, one hundred forty million, five hundred eleven thousand, five hundred".