Base | Representation |
---|---|
bin | 11000101000000110… |
… | …10111110010111111 |
3 | 1021010102021011022000 |
4 | 30110003113302333 |
5 | 204034130030421 |
6 | 10023534553343 |
7 | 645431310633 |
oct | 142403276277 |
9 | 37112234260 |
10 | 13221330111 |
11 | 5675107000 |
12 | 268b968853 |
13 | 13291b6972 |
14 | 8d5d00dc3 |
15 | 525ac1226 |
hex | 3140d7cbf |
13221330111 has 64 divisors (see below), whose sum is σ = 21821798400. Its totient is φ = 7909799040.
The previous prime is 13221330079. The next prime is 13221330149. The reversal of 13221330111 is 11103312231.
13221330111 is a `hidden beast` number, since 1 + 3 + 221 + 330 + 111 = 666.
It is not a de Polignac number, because 13221330111 - 25 = 13221330079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13221330191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2836695 + ... + 2841351.
It is an arithmetic number, because the mean of its divisors is an integer number (340965600).
Almost surely, 213221330111 is an apocalyptic number.
13221330111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13221330111 is a deficient number, since it is larger than the sum of its proper divisors (8600468289).
13221330111 is an equidigital number, since it uses as much as digits as its factorization.
13221330111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4778 (or 4750 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 13221330111 its reverse (11103312231), we get a palindrome (24324642342).
The spelling of 13221330111 in words is "thirteen billion, two hundred twenty-one million, three hundred thirty thousand, one hundred eleven".
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