Base | Representation |
---|---|
bin | 11110000100000011110000… |
… | …010001010010111111011101 |
3 | 122100011010201100021110000212 |
4 | 132010003300101102333131 |
5 | 114312244140400244031 |
6 | 1145113100320502205 |
7 | 36564413254003412 |
oct | 3604036021227735 |
9 | 570133640243025 |
10 | 132220304306141 |
11 | 39147352893a07 |
12 | 129b522047a965 |
13 | 58a142388b14c |
14 | 24916d55ca109 |
15 | 104454832612b |
hex | 7840f0452fdd |
132220304306141 has 2 divisors, whose sum is σ = 132220304306142. Its totient is φ = 132220304306140.
The previous prime is 132220304306117. The next prime is 132220304306173. The reversal of 132220304306141 is 141603403022231.
It is an a-pointer prime, because the next prime (132220304306173) can be obtained adding 132220304306141 to its sum of digits (32).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94819802102116 + 37400502204025 = 9737546^2 + 6115595^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132220304306141 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132220304306098 and 132220304306107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132220304306341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110152153070 + 66110152153071.
It is an arithmetic number, because the mean of its divisors is an integer number (66110152153071).
Almost surely, 2132220304306141 is an apocalyptic number.
It is an amenable number.
132220304306141 is a deficient number, since it is larger than the sum of its proper divisors (1).
132220304306141 is an equidigital number, since it uses as much as digits as its factorization.
132220304306141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 132220304306141 its reverse (141603403022231), we get a palindrome (273823707328372).
The spelling of 132220304306141 in words is "one hundred thirty-two trillion, two hundred twenty billion, three hundred four million, three hundred six thousand, one hundred forty-one".
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