Base | Representation |
---|---|
bin | 11110000100000110010010… |
… | …110011100101000011100100 |
3 | 122100011101202101102002221112 |
4 | 132010012102303211003210 |
5 | 114312320231441431040 |
6 | 1145114231051404152 |
7 | 36564540655146233 |
oct | 3604062263450344 |
9 | 570141671362845 |
10 | 132223031202020 |
11 | 39148522080170 |
12 | 129b5861753658 |
13 | 58a17698009c5 |
14 | 24918b3820b1a |
15 | 1044657920365 |
hex | 784192ce50e4 |
132223031202020 has 48 divisors (see below), whose sum is σ = 302921470268928. Its totient is φ = 48079431452160.
The previous prime is 132223031202001. The next prime is 132223031202077. The reversal of 132223031202020 is 20202130322231.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4088372 + ... + 16767851.
It is an arithmetic number, because the mean of its divisors is an integer number (6310863963936).
Almost surely, 2132223031202020 is an apocalyptic number.
132223031202020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132223031202020 is an abundant number, since it is smaller than the sum of its proper divisors (170698439066908).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132223031202020 is a wasteful number, since it uses less digits than its factorization.
132223031202020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20885060 (or 20885058 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 132223031202020 its reverse (20202130322231), we get a palindrome (152425161524251).
The spelling of 132223031202020 in words is "one hundred thirty-two trillion, two hundred twenty-three billion, thirty-one million, two hundred two thousand, twenty".
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