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132230210081 is a prime number
BaseRepresentation
bin111101100100110001…
…0001110001000100001
3110122022100110122201012
41323021202032020201
54131301413210311
6140425024150305
712360534145364
oct1731142161041
9418270418635
10132230210081
1151095562a62
1221763768395
13c613c52978
14658576c0db
15368da4b78b
hex1ec988e221

132230210081 has 2 divisors, whose sum is σ = 132230210082. Its totient is φ = 132230210080.

The previous prime is 132230210053. The next prime is 132230210083. The reversal of 132230210081 is 180012032231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67226118400 + 65004091681 = 259280^2 + 254959^2 .

It is a cyclic number.

It is not a de Polignac number, because 132230210081 - 210 = 132230209057 is a prime.

It is a super-2 number, since 2×1322302100812 (a number of 23 digits) contains 22 as substring.

Together with 132230210083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132230210083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66115105040 + 66115105041.

It is an arithmetic number, because the mean of its divisors is an integer number (66115105041).

Almost surely, 2132230210081 is an apocalyptic number.

It is an amenable number.

132230210081 is a deficient number, since it is larger than the sum of its proper divisors (1).

132230210081 is an equidigital number, since it uses as much as digits as its factorization.

132230210081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

The spelling of 132230210081 in words is "one hundred thirty-two billion, two hundred thirty million, two hundred ten thousand, eighty-one".