Base | Representation |
---|---|
bin | 11000101000010011… |
… | …10111100010110011 |
3 | 1021010112110200020101 |
4 | 30110021313202303 |
5 | 204040044024021 |
6 | 10024035253231 |
7 | 645451632436 |
oct | 142411674263 |
9 | 37115420211 |
10 | 13223033011 |
11 | 567606a461 |
12 | 269044a217 |
13 | 1329661ab6 |
14 | 8d622581d |
15 | 525d0aa91 |
hex | 3142778b3 |
13223033011 has 4 divisors (see below), whose sum is σ = 13296088624. Its totient is φ = 13149977400.
The previous prime is 13223032997. The next prime is 13223033023. The reversal of 13223033011 is 11033032231.
13223033011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11033032231 = 13 ⋅848694787.
It is a cyclic number.
It is not a de Polignac number, because 13223033011 - 225 = 13189478579 is a prime.
It is a super-2 number, since 2×132230330112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13223033011.
It is not an unprimeable number, because it can be changed into a prime (13223033051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36527535 + ... + 36527896.
It is an arithmetic number, because the mean of its divisors is an integer number (3324022156).
Almost surely, 213223033011 is an apocalyptic number.
13223033011 is a deficient number, since it is larger than the sum of its proper divisors (73055613).
13223033011 is an equidigital number, since it uses as much as digits as its factorization.
13223033011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73055612.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 13223033011 its reverse (11033032231), we get a palindrome (24256065242).
The spelling of 13223033011 in words is "thirteen billion, two hundred twenty-three million, thirty-three thousand, eleven".
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