Base | Representation |
---|---|
bin | 10011001111100001010… |
… | …001001010110001011000 |
3 | 11200102011202100011210012 |
4 | 103033201101022301120 |
5 | 133131120042142130 |
6 | 2451245541541052 |
7 | 164351451246026 |
oct | 23174121126130 |
9 | 4612152304705 |
10 | 1322334334040 |
11 | 46a8872929a5 |
12 | 19433b114788 |
13 | 979072a8b05 |
14 | 480038b9716 |
15 | 245e4a95995 |
hex | 133e144ac58 |
1322334334040 has 32 divisors (see below), whose sum is σ = 3017157219360. Its totient is φ = 521483961600.
The previous prime is 1322334333973. The next prime is 1322334334103. The reversal of 1322334334040 is 404334332231.
It is a junction number, because it is equal to n+sod(n) for n = 1322334333988 and 1322334334006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 232802501 + ... + 232808180.
It is an arithmetic number, because the mean of its divisors is an integer number (94286163105).
Almost surely, 21322334334040 is an apocalyptic number.
1322334334040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1322334334040 is an abundant number, since it is smaller than the sum of its proper divisors (1694822885320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1322334334040 is a wasteful number, since it uses less digits than its factorization.
1322334334040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 465610763 (or 465610759 counting only the distinct ones).
The product of its (nonzero) digits is 62208, while the sum is 32.
Adding to 1322334334040 its reverse (404334332231), we get a palindrome (1726668666271).
The spelling of 1322334334040 in words is "one trillion, three hundred twenty-two billion, three hundred thirty-four million, three hundred thirty-four thousand, forty".
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