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132236557421 is a prime number
BaseRepresentation
bin111101100100111101…
…0011011110001101101
3110122022210102010121212
41323021322123301231
54131310024314141
6140425412204205
712360642122633
oct1731172336155
9418283363555
10132236557421
11510990a88a1
1221765909665
13c615365aa7
146586541353
15368e3a22eb
hex1ec9e9bc6d

132236557421 has 2 divisors, whose sum is σ = 132236557422. Its totient is φ = 132236557420.

The previous prime is 132236557417. The next prime is 132236557423. The reversal of 132236557421 is 124755632231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125255119396 + 6981438025 = 353914^2 + 83555^2 .

It is a cyclic number.

It is not a de Polignac number, because 132236557421 - 22 = 132236557417 is a prime.

Together with 132236557423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132236557423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66118278710 + 66118278711.

It is an arithmetic number, because the mean of its divisors is an integer number (66118278711).

Almost surely, 2132236557421 is an apocalyptic number.

It is an amenable number.

132236557421 is a deficient number, since it is larger than the sum of its proper divisors (1).

132236557421 is an equidigital number, since it uses as much as digits as its factorization.

132236557421 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 302400, while the sum is 41.

The spelling of 132236557421 in words is "one hundred thirty-two billion, two hundred thirty-six million, five hundred fifty-seven thousand, four hundred twenty-one".