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13224940109 is a prime number
BaseRepresentation
bin11000101000100010…
…01001001001001101
31021010200001120021122
430110101021021031
5204041041040414
610024144210325
7645504064463
oct142421111115
937120046248
1013224940109
115677152277
1226910099a5
131329b7bb64
148d65a0833
15526085b8e
hex31444924d

13224940109 has 2 divisors, whose sum is σ = 13224940110. Its totient is φ = 13224940108.

The previous prime is 13224940087. The next prime is 13224940111. The reversal of 13224940109 is 90104942231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11822212900 + 1402727209 = 108730^2 + 37453^2 .

It is a cyclic number.

It is not a de Polignac number, because 13224940109 - 212 = 13224936013 is a prime.

Together with 13224940111, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13224940159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6612470054 + 6612470055.

It is an arithmetic number, because the mean of its divisors is an integer number (6612470055).

Almost surely, 213224940109 is an apocalyptic number.

It is an amenable number.

13224940109 is a deficient number, since it is larger than the sum of its proper divisors (1).

13224940109 is an equidigital number, since it uses as much as digits as its factorization.

13224940109 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 13224940109 in words is "thirteen billion, two hundred twenty-four million, nine hundred forty thousand, one hundred nine".