Base | Representation |
---|---|
bin | 11110000100100101011101… |
… | …111010110110011011010111 |
3 | 122100021121011010201212002001 |
4 | 132010211131322312123113 |
5 | 114313342304413412403 |
6 | 1145141444330300131 |
7 | 36600134311251133 |
oct | 3604453572663327 |
9 | 570247133655061 |
10 | 132256503654103 |
11 | 39160739435904 |
12 | 12a00243587647 |
13 | 58a497240857a |
14 | 249336b0d63c3 |
15 | 1045466313c1d |
hex | 78495deb66d7 |
132256503654103 has 2 divisors, whose sum is σ = 132256503654104. Its totient is φ = 132256503654102.
The previous prime is 132256503654101. The next prime is 132256503654173. The reversal of 132256503654103 is 301456305652231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132256503654103 - 21 = 132256503654101 is a prime.
Together with 132256503654101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132256503654101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66128251827051 + 66128251827052.
It is an arithmetic number, because the mean of its divisors is an integer number (66128251827052).
Almost surely, 2132256503654103 is an apocalyptic number.
132256503654103 is a deficient number, since it is larger than the sum of its proper divisors (1).
132256503654103 is an equidigital number, since it uses as much as digits as its factorization.
132256503654103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944000, while the sum is 46.
The spelling of 132256503654103 in words is "one hundred thirty-two trillion, two hundred fifty-six billion, five hundred three million, six hundred fifty-four thousand, one hundred three".
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