132256503654101 has 2 divisors, whose sum is σ = 132256503654102. Its totient is φ = 132256503654100.

The previous prime is 132256503654073. The next prime is 132256503654103. The reversal of 132256503654101 is 101456305652231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114730341000625 + 17526162653476 = 10711225^2 + 4186426^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132256503654101 is a prime.

Together with 132256503654103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132256503654103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66128251827050 + 66128251827051.

It is an arithmetic number, because the mean of its divisors is an integer number (66128251827051).

Almost surely, 2^{132256503654101} is an apocalyptic number.

It is an amenable number.

132256503654101 is a deficient number, since it is larger than the sum of its proper divisors (1).

132256503654101 is an equidigital number, since it uses as much as digits as its factorization.

132256503654101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 44.

The spelling of 132256503654101 in words is "one hundred thirty-two trillion, two hundred fifty-six billion, five hundred three million, six hundred fifty-four thousand, one hundred one".