132301033112440 has 16 divisors (see below), whose sum is σ = 297677324503080. Its totient is φ = 52920413244960.

The previous prime is 132301033112401. The next prime is 132301033112489. The reversal of 132301033112440 is 44211330103231.

It is a junction number, because it is equal to n+sod(n) for n = 132301033112399 and 132301033112408.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1653762913866 + ... + 1653762913945.

Almost surely, 2^{132301033112440} is an apocalyptic number.

132301033112440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132301033112440 is an abundant number, since it is smaller than the sum of its proper divisors (165376291390640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132301033112440 is a wasteful number, since it uses less digits than its factorization.

132301033112440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3307525827822 (or 3307525827818 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 132301033112440 its reverse (44211330103231), we get a palindrome (176512363215671).

The spelling of 132301033112440 in words is "one hundred thirty-two trillion, three hundred one billion, thirty-three million, one hundred twelve thousand, four hundred forty".