Base | Representation |
---|---|
bin | 11000101001001010… |
… | …00001000110010011 |
3 | 1021011000212020221212 |
4 | 30110211001012103 |
5 | 204043404300120 |
6 | 10024452010335 |
7 | 645566263664 |
oct | 142445010623 |
9 | 37130766855 |
10 | 13230150035 |
11 | 567a0905a3 |
12 | 26929009ab |
13 | 132ac8435b |
14 | 8d715936b |
15 | 5267646c5 |
hex | 314941193 |
13230150035 has 8 divisors (see below), whose sum is σ = 15898265280. Its totient is φ = 10569396544.
The previous prime is 13230149993. The next prime is 13230150097. The reversal of 13230150035 is 53005103231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13230150035 - 212 = 13230145939 is a prime.
It is a super-2 number, since 2×132301500352 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1836482 + ... + 1843671.
It is an arithmetic number, because the mean of its divisors is an integer number (1987283160).
Almost surely, 213230150035 is an apocalyptic number.
13230150035 is a deficient number, since it is larger than the sum of its proper divisors (2668115245).
13230150035 is an equidigital number, since it uses as much as digits as its factorization.
13230150035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3680877.
The product of its (nonzero) digits is 1350, while the sum is 23.
Adding to 13230150035 its reverse (53005103231), we get a palindrome (66235253266).
The spelling of 13230150035 in words is "thirteen billion, two hundred thirty million, one hundred fifty thousand, thirty-five".
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