Base | Representation |
---|---|
bin | 11110000101010000001000… |
… | …110110101001101000111111 |
3 | 122100102222102020101210022112 |
4 | 132011100020312221220333 |
5 | 114320120123202130142 |
6 | 1145214503002004235 |
7 | 36603345565340165 |
oct | 3605201066515077 |
9 | 570388366353275 |
10 | 132302321130047 |
11 | 39179110188702 |
12 | 12a090ab7a667b |
13 | 58a90947aab93 |
14 | 249567615d235 |
15 | 10467488cc382 |
hex | 785408da9a3f |
132302321130047 has 2 divisors, whose sum is σ = 132302321130048. Its totient is φ = 132302321130046.
The previous prime is 132302321130019. The next prime is 132302321130079. The reversal of 132302321130047 is 740031123203231.
It is an a-pointer prime, because the next prime (132302321130079) can be obtained adding 132302321130047 to its sum of digits (32).
It is a weak prime.
It is an emirp because it is prime and its reverse (740031123203231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132302321130047 - 26 = 132302321129983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132302321129995 and 132302321130022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132302321130017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151160565023 + 66151160565024.
It is an arithmetic number, because the mean of its divisors is an integer number (66151160565024).
Almost surely, 2132302321130047 is an apocalyptic number.
132302321130047 is a deficient number, since it is larger than the sum of its proper divisors (1).
132302321130047 is an equidigital number, since it uses as much as digits as its factorization.
132302321130047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 132302321130047 its reverse (740031123203231), we get a palindrome (872333444333278).
The spelling of 132302321130047 in words is "one hundred thirty-two trillion, three hundred two billion, three hundred twenty-one million, one hundred thirty thousand, forty-seven".
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