132302321130055 has 4 divisors (see below), whose sum is σ = 158762785356072. Its totient is φ = 105841856904040.

The previous prime is 132302321130047. The next prime is 132302321130079. The reversal of 132302321130055 is 550031123203231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 132302321130055 - 2³ = 132302321130047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132302321129999 and 132302321130026.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13230232113001 + ... + 13230232113010.

It is an arithmetic number, because the mean of its divisors is an integer number (39690696339018).

Almost surely, 2^{132302321130055} is an apocalyptic number.

132302321130055 is a deficient number, since it is larger than the sum of its proper divisors (26460464226017).

132302321130055 is an equidigital number, since it uses as much as digits as its factorization.

132302321130055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26460464226016.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 132302321130055 its reverse (550031123203231), we get a palindrome (682333444333286).

The spelling of 132302321130055 in words is "one hundred thirty-two trillion, three hundred two billion, three hundred twenty-one million, one hundred thirty thousand, fifty-five".