Base | Representation |
---|---|
bin | 111101100111001101… |
… | …0100110110111001111 |
3 | 110122112001120002222101 |
4 | 1323032122212313033 |
5 | 4131433344202203 |
6 | 140441111255531 |
7 | 12362550203365 |
oct | 1731632466717 |
9 | 418461502871 |
10 | 132312100303 |
11 | 51127805329 |
12 | 2178707a5a7 |
13 | c627bc5516 |
14 | 65925a7635 |
15 | 3695d2541d |
hex | 1ece6a6dcf |
132312100303 has 2 divisors, whose sum is σ = 132312100304. Its totient is φ = 132312100302.
The previous prime is 132312100301. The next prime is 132312100373. The reversal of 132312100303 is 303001213231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132312100303 - 21 = 132312100301 is a prime.
It is a super-2 number, since 2×1323121003032 (a number of 23 digits) contains 22 as substring.
Together with 132312100301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132312100301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156050151 + 66156050152.
It is an arithmetic number, because the mean of its divisors is an integer number (66156050152).
Almost surely, 2132312100303 is an apocalyptic number.
132312100303 is a deficient number, since it is larger than the sum of its proper divisors (1).
132312100303 is an equidigital number, since it uses as much as digits as its factorization.
132312100303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 132312100303 its reverse (303001213231), we get a palindrome (435313313534).
The spelling of 132312100303 in words is "one hundred thirty-two billion, three hundred twelve million, one hundred thousand, three hundred three".
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