Base | Representation |
---|---|
bin | 111101100111001101… |
… | …1000001111010011111 |
3 | 110122112001202201222002 |
4 | 1323032123001322133 |
5 | 4131433411223403 |
6 | 140441113512515 |
7 | 12362551144412 |
oct | 1731633017237 |
9 | 418461681862 |
10 | 132312211103 |
11 | 511278805a6 |
12 | 2178711273b |
13 | c627c33a97 |
14 | 65925d5b79 |
15 | 3695d48188 |
hex | 1ece6c1e9f |
132312211103 has 2 divisors, whose sum is σ = 132312211104. Its totient is φ = 132312211102.
The previous prime is 132312211093. The next prime is 132312211121. The reversal of 132312211103 is 301112213231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132312211103 - 236 = 63592734367 is a prime.
It is a super-3 number, since 3×1323122111033 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132312211183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156105551 + 66156105552.
It is an arithmetic number, because the mean of its divisors is an integer number (66156105552).
Almost surely, 2132312211103 is an apocalyptic number.
132312211103 is a deficient number, since it is larger than the sum of its proper divisors (1).
132312211103 is an equidigital number, since it uses as much as digits as its factorization.
132312211103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 132312211103 its reverse (301112213231), we get a palindrome (433424424334).
The spelling of 132312211103 in words is "one hundred thirty-two billion, three hundred twelve million, two hundred eleven thousand, one hundred three".
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