1323130013000 has 64 divisors (see below), whose sum is σ = 3099738985200. Its totient is φ = 528634099200.

The previous prime is 1323130012933. The next prime is 1323130013083. The reversal of 1323130013000 is 3100313231.

It can be written as a sum of positive squares in 8 ways, for example, as 479631042916 + 843498970084 = 692554^2 + 918422^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 1323130013000.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85046 + ... + 1628954.

Almost surely, 2^{1323130013000} is an apocalyptic number.

1323130013000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1323130013000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1549869492600).

1323130013000 is an abundant number, since it is smaller than the sum of its proper divisors (1776608972200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1323130013000 is a wasteful number, since it uses less digits than its factorization.

1323130013000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1544787 (or 1544773 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 1323130013000 its reverse (3100313231), we get a palindrome (1326230326231).

The spelling of 1323130013000 in words is "one trillion, three hundred twenty-three billion, one hundred thirty million, thirteen thousand".