Base | Representation |
---|---|
bin | 10011010000010100111… |
… | …011101111100111001000 |
3 | 11200111102011101010102101 |
4 | 103100110323233213020 |
5 | 133134403442224000 |
6 | 2451511544243144 |
7 | 164412105024505 |
oct | 23202473574710 |
9 | 4614364333371 |
10 | 1323201133000 |
11 | 4701915a887a |
12 | 1945414704b4 |
13 | 97a14a494c6 |
14 | 48086a724ac |
15 | 24645c14e6a |
hex | 13414eef9c8 |
1323201133000 has 32 divisors (see below), whose sum is σ = 3096290653560. Its totient is φ = 529280452800.
The previous prime is 1323201132991. The next prime is 1323201133057. The reversal of 1323201133000 is 3311023231.
It can be written as a sum of positive squares in 4 ways, for example, as 216930514564 + 1106270618436 = 465758^2 + 1051794^2 .
It is a super-2 number, since 2×13232011330002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 661599567 + ... + 661601566.
Almost surely, 21323201133000 is an apocalyptic number.
1323201133000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1323201133000 is an abundant number, since it is smaller than the sum of its proper divisors (1773089520560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1323201133000 is a wasteful number, since it uses less digits than its factorization.
1323201133000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1323201154 (or 1323201140 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 1323201133000 its reverse (3311023231), we get a palindrome (1326512156231).
The spelling of 1323201133000 in words is "one trillion, three hundred twenty-three billion, two hundred one million, one hundred thirty-three thousand".
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