Base | Representation |
---|---|
bin | 111101100111011100… |
… | …1100000010110100111 |
3 | 110122112121210121210222 |
4 | 1323032321200112213 |
5 | 4131442432400403 |
6 | 140442001034555 |
7 | 12363006100100 |
oct | 1731671402647 |
9 | 418477717728 |
10 | 132320200103 |
11 | 51131337883 |
12 | 21789925a5b |
13 | c6297a01c0 |
14 | 65936b53a7 |
15 | 36968c5338 |
hex | 1ecee605a7 |
132320200103 has 24 divisors (see below), whose sum is σ = 165920555808. Its totient is φ = 104593882176.
The previous prime is 132320200093. The next prime is 132320200127. The reversal of 132320200103 is 301002023231.
It is not a de Polignac number, because 132320200103 - 214 = 132320183719 is a prime.
It is a super-2 number, since 2×1323202001032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132320200193) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 579425 + ... + 774837.
It is an arithmetic number, because the mean of its divisors is an integer number (6913356492).
Almost surely, 2132320200103 is an apocalyptic number.
132320200103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
132320200103 is a deficient number, since it is larger than the sum of its proper divisors (33600355705).
132320200103 is a wasteful number, since it uses less digits than its factorization.
132320200103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 196503 (or 196496 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 132320200103 its reverse (301002023231), we get a palindrome (433322223334).
The spelling of 132320200103 in words is "one hundred thirty-two billion, three hundred twenty million, two hundred thousand, one hundred three".
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