Base | Representation |
---|---|
bin | 11110000101100001101110… |
… | …110010111011100010100000 |
3 | 122100111210011201120211221201 |
4 | 132011201232302323202200 |
5 | 114320422320043100000 |
6 | 1145231305243530544 |
7 | 36604614653210032 |
oct | 3605415662734240 |
9 | 570453151524851 |
10 | 132321211300000 |
11 | 39186124198a08 |
12 | 12a108a1b29a54 |
13 | 58aaab5272738 |
14 | 2496548ca7c52 |
15 | 1046ea1ebe96a |
hex | 78586ecbb8a0 |
132321211300000 has 144 divisors (see below), whose sum is σ = 326293285893120. Its totient is φ = 52817967520000.
The previous prime is 132321211299919. The next prime is 132321211300001. The reversal of 132321211300000 is 3112123231.
It is not an unprimeable number, because it can be changed into a prime (132321211300001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 46518777 + ... + 49281223.
It is an arithmetic number, because the mean of its divisors is an integer number (2265925596480).
Almost surely, 2132321211300000 is an apocalyptic number.
132321211300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132321211300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (163146642946560).
132321211300000 is an abundant number, since it is smaller than the sum of its proper divisors (193972074593120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132321211300000 is an frugal number, since it uses more digits than its factorization.
132321211300000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2762961 (or 2762933 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 132321211300000 its reverse (3112123231), we get a palindrome (132324323423231).
The spelling of 132321211300000 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, two hundred eleven million, three hundred thousand".
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