Base | Representation |
---|---|
bin | 1100000010001110000001… |
… | …0011011001101100000000 |
3 | 1201211222210010021200121012 |
4 | 3000203200103121230000 |
5 | 3213244133142012031 |
6 | 44050452323020052 |
7 | 2533666541031164 |
oct | 300434023315400 |
9 | 51758703250535 |
10 | 13232262454016 |
11 | 4241853211131 |
12 | 1598601b0a628 |
13 | 74ca48cc9c68 |
14 | 33a632c08ca4 |
15 | 17e30518bb2b |
hex | c08e04d9b00 |
13232262454016 has 72 divisors (see below), whose sum is σ = 28868679149184. Its totient is φ = 6026077716480.
The previous prime is 13232262453989. The next prime is 13232262454069. The reversal of 13232262454016 is 61045426223231.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48905435 + ... + 49175258.
It is an arithmetic number, because the mean of its divisors is an integer number (400953877072).
Almost surely, 213232262454016 is an apocalyptic number.
13232262454016 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
13232262454016 is an abundant number, since it is smaller than the sum of its proper divisors (15636416695168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13232262454016 is an equidigital number, since it uses as much as digits as its factorization.
13232262454016 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98080757 (or 98080743 counting only the distinct ones).
The product of its (nonzero) digits is 414720, while the sum is 41.
Adding to 13232262454016 its reverse (61045426223231), we get a palindrome (74277688677247).
The spelling of 13232262454016 in words is "thirteen trillion, two hundred thirty-two billion, two hundred sixty-two million, four hundred fifty-four thousand, sixteen".
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