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13233041041440 = 2535116197467907
BaseRepresentation
bin1100000010010000111010…
…1101011110100000100000
31201212001210101100000202110
43000210032231132200200
53213302232001311230
644051101454515320
72534025043643313
oct300441655364040
951761711300673
1013233041041440
114242112757410
12159879a805b40
1374cb413c378c
1433a6a839c97a
1517e34d6d44b0
hexc090eb5e820

13233041041440 has 768 divisors, whose sum is σ = 46847077595136. Its totient is φ = 3112766668800.

The previous prime is 13233041041387. The next prime is 13233041041447. The reversal of 13233041041440 is 4414014033231.

It is a super-2 number, since 2×132330410414402 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 13233041041398 and 13233041041407.

It is not an unprimeable number, because it can be changed into a prime (13233041041447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 14589901467 + ... + 14589902373.

It is an arithmetic number, because the mean of its divisors is an integer number (60998798952).

Almost surely, 213233041041440 is an apocalyptic number.

13233041041440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13233041041440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23423538797568).

13233041041440 is an abundant number, since it is smaller than the sum of its proper divisors (33614036553696).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13233041041440 is a wasteful number, since it uses less digits than its factorization.

13233041041440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1561 (or 1553 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 13233041041440 its reverse (4414014033231), we get a palindrome (17647055074671).

The spelling of 13233041041440 in words is "thirteen trillion, two hundred thirty-three billion, forty-one million, forty-one thousand, four hundred forty".