13234000181 has 2 divisors, whose sum is σ = 13234000182. Its totient is φ = 13234000180.

The previous prime is 13234000139. The next prime is 13234000237. The reversal of 13234000181 is 18100043231.

13234000181 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8816271025 + 4417729156 = 93895^2 + 66466^2 .

It is an emirp because it is prime and its reverse (18100043231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13234000181 is a prime.

It is a super-2 number, since 2×13234000181² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13234008181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6617000090 + 6617000091.

It is an arithmetic number, because the mean of its divisors is an integer number (6617000091).

Almost surely, 2^13234000181 is an apocalyptic number.

It is an amenable number.

13234000181 is a deficient number, since it is larger than the sum of its proper divisors (1).

13234000181 is an equidigital number, since it uses as much as digits as its factorization.

13234000181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

The spelling of 13234000181 in words is "thirteen billion, two hundred thirty-four million, one hundred eighty-one", and thus it is an aban number.