Search a number
-
+
1323434343232 = 26291613442069
BaseRepresentation
bin10011010000100010110…
…101010111101101000000
311200112000102012102201101
4103100202311113231000
5133140343142440412
62451551034544144
7164420636210641
oct23204265275500
94615012172641
101323434343232
114702a1204101
121945a7598054
1397a51160a21
14480a9a1b6c8
152465b42e457
hex13422d57b40

1323434343232 has 56 divisors (see below), whose sum is σ = 2718438733800. Its totient is φ = 638501799936.

The previous prime is 1323434343169. The next prime is 1323434343239. The reversal of 1323434343232 is 2323434343231.

It can be written as a sum of positive squares in 4 ways, for example, as 661710663936 + 661723679296 = 813456^2 + 813464^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1323434343191 and 1323434343200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1323434343239) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2772694 + ... + 3214762.

Almost surely, 21323434343232 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1323434343232, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1359219366900).

1323434343232 is an abundant number, since it is smaller than the sum of its proper divisors (1395004390568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1323434343232 is a wasteful number, since it uses less digits than its factorization.

1323434343232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443723 (or 443713 counting only the distinct ones).

The product of its digits is 373248, while the sum is 37.

Adding to 1323434343232 its reverse (2323434343231), we get a palindrome (3646868686463).

Subtracting 1323434343232 from its reverse (2323434343231), we obtain a palindrome (999999999999).

It can be divided in two parts, 13234343432 and 32, that multiplied together give a square (423498989824 = 6507682).

The spelling of 1323434343232 in words is "one trillion, three hundred twenty-three billion, four hundred thirty-four million, three hundred forty-three thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 29 32 58 64 116 232 464 928 1613 1856 3226 6452 12904 25808 46777 51616 93554 103232 187108 374216 442069 748432 884138 1496864 1768276 2993728 3536552 7073104 12820001 14146208 25640002 28292416 51280004 102560008 205120016 410240032 713057297 820480064 1426114594 2852229188 5704458376 11408916752 20678661613 22817833504 41357323226 45635667008 82714646452 165429292904 330858585808 661717171616 1323434343232