Base | Representation |
---|---|
bin | 11000101001110001… |
… | …10100001101001001 |
3 | 1021011101121221101200 |
4 | 30110320310031021 |
5 | 204101221340410 |
6 | 10025155134413 |
7 | 645661351251 |
oct | 142470641511 |
9 | 37141557350 |
10 | 13235340105 |
11 | 5682005a09 |
12 | 26945a4409 |
13 | 132c0807c0 |
14 | 8d7b0a961 |
15 | 526e3c3c0 |
hex | 314e34349 |
13235340105 has 96 divisors (see below), whose sum is σ = 25622338560. Its totient is φ = 6276165120.
The previous prime is 13235340091. The next prime is 13235340113. The reversal of 13235340105 is 50104353231.
13235340105 is a `hidden beast` number, since 1 + 3 + 23 + 534 + 0 + 105 = 666.
It is not a de Polignac number, because 13235340105 - 222 = 13231145801 is a prime.
It is a super-2 number, since 2×132353401052 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4151322 + ... + 4154508.
It is an arithmetic number, because the mean of its divisors is an integer number (266899360).
Almost surely, 213235340105 is an apocalyptic number.
13235340105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13235340105 is a deficient number, since it is larger than the sum of its proper divisors (12386998455).
13235340105 is a wasteful number, since it uses less digits than its factorization.
13235340105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3471 (or 3468 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 13235340105 its reverse (50104353231), we get a palindrome (63339693336).
The spelling of 13235340105 in words is "thirteen billion, two hundred thirty-five million, three hundred forty thousand, one hundred five".
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