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13235340142 = 26617670071
BaseRepresentation
bin11000101001110001…
…10100001101101110
31021011101121221110001
430110320310031232
5204101221341032
610025155134514
7645661351333
oct142470641556
937141557401
1013235340142
115682005a42
1226945a443a
13132c08081b
148d7b0a98a
15526e3c3e7
hex314e3436e

13235340142 has 4 divisors (see below), whose sum is σ = 19853010216. Its totient is φ = 6617670070.

The previous prime is 13235340137. The next prime is 13235340199. The reversal of 13235340142 is 24104353231.

It is a happy number.

13235340142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×132353401423 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13235340142.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3308835034 + ... + 3308835037.

It is an arithmetic number, because the mean of its divisors is an integer number (4963252554).

Almost surely, 213235340142 is an apocalyptic number.

13235340142 is a deficient number, since it is larger than the sum of its proper divisors (6617670074).

13235340142 is an equidigital number, since it uses as much as digits as its factorization.

13235340142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6617670073.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 13235340142 its reverse (24104353231), we get a palindrome (37339693373).

The spelling of 13235340142 in words is "thirteen billion, two hundred thirty-five million, three hundred forty thousand, one hundred forty-two".

Divisors: 1 2 6617670071 13235340142