132404040031 has 4 divisors (see below), whose sum is σ = 140192512992. Its totient is φ = 124615567072.

The previous prime is 132404039923. The next prime is 132404040047. The reversal of 132404040031 is 130040404231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 130040404231 = 17 ⋅7649435543.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132404040031 is a prime.

It is a super-2 number, since 2×132404040031² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132404039984 and 132404040011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132404040061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3894236455 + ... + 3894236488.

It is an arithmetic number, because the mean of its divisors is an integer number (35048128248).

Almost surely, 2^132404040031 is an apocalyptic number.

132404040031 is a deficient number, since it is larger than the sum of its proper divisors (7788472961).

132404040031 is an equidigital number, since it uses as much as digits as its factorization.

132404040031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7788472960.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 132404040031 its reverse (130040404231), we get a palindrome (262444444262).

The spelling of 132404040031 in words is "one hundred thirty-two billion, four hundred four million, forty thousand, thirty-one".