Base | Representation |
---|---|
bin | 1100000010101111101000… |
… | …1001111110010011100101 |
3 | 1201212212001222220122210020 |
4 | 3000223322021332103211 |
5 | 3213421123221443043 |
6 | 44054543551345353 |
7 | 2534436262000200 |
oct | 300537211762345 |
9 | 51785058818706 |
10 | 13241286124773 |
11 | 42456638aa573 |
12 | 159a2bbb22259 |
13 | 750856647405 |
14 | 33ac4b422937 |
15 | 17e682491e83 |
hex | c0afa27e4e5 |
13241286124773 has 12 divisors (see below), whose sum is σ = 20537505010080. Its totient is φ = 7566449214072.
The previous prime is 13241286124747. The next prime is 13241286124813. The reversal of 13241286124773 is 37742168214231.
It is a happy number.
It is not a de Polignac number, because 13241286124773 - 210 = 13241286123749 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13241286128773) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 45038388033 + ... + 45038388326.
It is an arithmetic number, because the mean of its divisors is an integer number (1711458750840).
Almost surely, 213241286124773 is an apocalyptic number.
It is an amenable number.
13241286124773 is a deficient number, since it is larger than the sum of its proper divisors (7296218885307).
13241286124773 is an equidigital number, since it uses as much as digits as its factorization.
13241286124773 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90076776376 (or 90076776369 counting only the distinct ones).
The product of its digits is 2709504, while the sum is 51.
The spelling of 13241286124773 in words is "thirteen trillion, two hundred forty-one billion, two hundred eighty-six million, one hundred twenty-four thousand, seven hundred seventy-three".
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