Base | Representation |
---|---|
bin | 1100000010110010000111… |
… | …1011101100010111001101 |
3 | 1201212220210111122022012110 |
4 | 3000230201323230113031 |
5 | 3213424010042014101 |
6 | 44055134111054233 |
7 | 2534461644224622 |
oct | 300544173542715 |
9 | 51786714568173 |
10 | 13241953469901 |
11 | 4245976575872 |
12 | 159a467511379 |
13 | 7509319922a0 |
14 | 33acb1cda349 |
15 | 17e6c0d63cd6 |
hex | c0b21eec5cd |
13241953469901 has 128 divisors (see below), whose sum is σ = 20615430528000. Its totient is φ = 7492720435200.
The previous prime is 13241953469869. The next prime is 13241953469917. The reversal of 13241953469901 is 10996435914231.
13241953469901 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13241953469901 - 25 = 13241953469869 is a prime.
It is a super-2 number, since 2×132419534699012 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13241953469981) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 10178287951 + ... + 10178289251.
It is an arithmetic number, because the mean of its divisors is an integer number (161058051000).
Almost surely, 213241953469901 is an apocalyptic number.
It is an amenable number.
13241953469901 is a deficient number, since it is larger than the sum of its proper divisors (7373477058099).
13241953469901 is a wasteful number, since it uses less digits than its factorization.
13241953469901 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2791.
The product of its (nonzero) digits is 6298560, while the sum is 57.
The spelling of 13241953469901 in words is "thirteen trillion, two hundred forty-one billion, nine hundred fifty-three million, four hundred sixty-nine thousand, nine hundred one".
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