Base | Representation |
---|---|
bin | 111101101010110100… |
… | …1000110101111110111 |
3 | 110122211111200210112112 |
4 | 1323111221012233313 |
5 | 4132210413411211 |
6 | 140501122041235 |
7 | 12365551554146 |
oct | 1732551065767 |
9 | 418744623475 |
10 | 132433341431 |
11 | 5118a194606 |
12 | 217bb7a921b |
13 | c647065331 |
14 | 65a472775d |
15 | 36a17c388b |
hex | 1ed5a46bf7 |
132433341431 has 2 divisors, whose sum is σ = 132433341432. Its totient is φ = 132433341430.
The previous prime is 132433341427. The next prime is 132433341433. The reversal of 132433341431 is 134143334231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132433341431 - 22 = 132433341427 is a prime.
It is a super-2 number, since 2×1324333414312 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 132433341433, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132433341433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66216670715 + 66216670716.
It is an arithmetic number, because the mean of its divisors is an integer number (66216670716).
Almost surely, 2132433341431 is an apocalyptic number.
132433341431 is a deficient number, since it is larger than the sum of its proper divisors (1).
132433341431 is an equidigital number, since it uses as much as digits as its factorization.
132433341431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 31104, while the sum is 32.
Adding to 132433341431 its reverse (134143334231), we get a palindrome (266576675662).
The spelling of 132433341431 in words is "one hundred thirty-two billion, four hundred thirty-three million, three hundred forty-one thousand, four hundred thirty-one".
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